** Posted On** 2017-02-10

** Answer** Case #1: P gets a window seat.
Probability of P getting a window seat is 2/6. If it happens, then the probability of getting a neighbouring seat is 1/59.
Case #2: P doesn't get a window seat
Probability of P not getting a window seat is 4/6. If it happens, then the probability of getting a neighbouring seat is 2/59.
Thus, (2/6 * 1/59) + (4/6 * 2/59) = 5/177
Another way of solving
The seats can be AB, BC, CD, DE, EF. Since there are 10 rows, the total number of possibilities are 5*10=50.
From 60 seats, if we have to select two seats, we can do it in 60C2 ways = 1770 ways.
Thus, 50/1770 = 5/177.

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- Shreyans Jain, Ganeshram G.S