Posted On 2017-02-10
Answer Case #1: P gets a window seat. Probability of P getting a window seat is 2/6. If it happens, then the probability of getting a neighbouring seat is 1/59. Case #2: P doesn't get a window seat Probability of P not getting a window seat is 4/6. If it happens, then the probability of getting a neighbouring seat is 2/59. Thus, (2/6 * 1/59) + (4/6 * 2/59) = 5/177 Another way of solving The seats can be AB, BC, CD, DE, EF. Since there are 10 rows, the total number of possibilities are 5*10=50. From 60 seats, if we have to select two seats, we can do it in 60C2 ways = 1770 ways. Thus, 50/1770 = 5/177.